Given :
Point A(2,3)
(distance along x-axis)Tx = 3 units
(distance along y-axis)Ty = 4 units
To find :
A'(x', y')
Solution :
We know that A' = A + T
In matrix form
[x' y'] = [x y] + [Tx Ty]
[x' y'] = [2 3] + [3 4]
[x' y'] = [5 7]
A'(x', y') = (5,7)